ansible 实现任务计划

2018-08-04

ansible 实现任务计划

 需用模块 cron

 创建一个任务计划

[root@server ~]# ansible client.test.com -m cron -a "name=test_cron job='/bin/bash /usr/local/sbin/1.sh' weekday=6"

client.test.com | SUCCESS => {

    "changed": true,

    "envs": [],

    "jobs": [

        "test_cron"

    ]

}

 查看一下

[root@server ~]# ansible client.test.com -m shell -a "crontab -l"

client.test.com | SUCCESS | rc=0 >>

*/10 * * * * ntpdate s1a.time.edu.cn >/dev/null 2>&1

#Ansible: test_cron

* * * * 6 /bin/bash /usr/local/sbin/1.sh

 删除这个 test_cron

[root@server ~]# ansible client.test.com -m cron -a "name=test_cron state=absent"

client.test.com | SUCCESS => {

    "changed": true,

    "envs": [],

    "jobs": []

}

[root@server ~]# ansible client.test.com -m shell -a "crontab -l"               client.test.com | SUCCESS | rc=0 >>

*/10 * * * * ntpdate s1a.time.edu.cn >/dev/null 2>&1

 任务计划列表里已经没有了 test_cron 的 job

 其他的时间表示:分钟 minute 小时 hour 日期 day 月份 month

[root@server ~]# ansible client.test.com -m cron -a "name=test_cron job='/bin/bash /usr/local/sbin/1.sh' day='1-10' weekday=6"

[root@server ~]# ansible client.test.com -m shell -a "crontab -l"               client.test.com | SUCCESS | rc=0 >>

*/10 * * * * ntpdate s1a.time.edu.cn >/dev/null 2>&1

#Ansible: test_cron

* * 1-10 * 6 /bin/bash /usr/local/sbin/1.sh




[root@server ~]# ansible client.test.com -m cron -a "name=test_cron job='/bin/bash /usr/local/sbin/1.sh' day='1,5,10' weekday=6"

[root@server ~]# ansible client.test.com -m shell -a "crontab -l"               client.test.com | SUCCESS | rc=0 >>

*/10 * * * * ntpdate s1a.time.edu.cn >/dev/null 2>&1

#Ansible: test_cron

* * 1,5,10 * 6 /bin/bash /usr/local/sbin/1.sh

标题:ansible 实现任务计划
作者:散宜生
地址:https://17kblog.com/articles/2018/08/04/1533356474832.html